MeOSiF3 is formed when gaseous MeOSiCl3 is passed through SbF3; its reaction with BBr3 provides a convenient preparation of F3SiBr. Similarly BF3 and BCl3 yield SiF4 and F3SiCl respectively. The other product in these reactions is MeOBX2 (X = Br, F, Cl respectively), but the methoxy boron dibromide decomposes to give methyl bromide and boron oxybromides.
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